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View Full Version : Serious Genetics Help Needed


csampel
03-04-2007, 11:49 PM
Anyone that can point me in the right direction would be my HERO!

I'm getting ready to purchase a 0.1 DH Snow BCI and a 1.0 Anery Het Snow BCI and a 0.1 Albino Het Snow BCI. All should be Kahl Line. So what I'm trying to figure out and I can't get the square right is what will I get if I go:

0.1 DH Snow BCI x 1.0 Anery Het Snow BCI
and
0.1 Albino Het Snow BCI x 1.0 Anery Het Snow BCI

I'm sure someone has already figured this out and it's sitting somewhere on a web page somewhere but I can't find it and I've been working on the squares for 2 hours and I just don't trust my results.

Can Anyone Help???

Randy_T.
03-05-2007, 12:18 PM
www.geneticswizard.com

You will have lots of fun using it. I know I have. Just to see what crazy outcomes I could create.

csampel
03-05-2007, 03:50 PM
I have never been able to make that thing work for me. I think I need a teacher or to go back and take some higher science.:D

Bernie
03-05-2007, 04:26 PM
Allright lets break it down a little bit and try to work it out.......

0.1 DH Snow BCI x 1.0 Anery Het Snow BCI

First lets look at it as an anery x het anery which would result in half anery and half hat anery

now lets look at the other half the het albino x het albino which gives you 25% albino 50% het albino and 25% normal (being no way to differentiate the hets from the normals lets call them all 66% possible hets)

now to put these two together 25% of the anerys will be snow and the others will anery 66% possible het snow (albino)

same with the het anerys 25% will be albinos het snow (anery) and the others will be het anery 66% possible het albino.

So..........

25% of half would be 1 out of 8 will be snow

75% of half would be 3 out of 8 will be anery 66% possible het snow

25% of half would be 1 out of 8 will be albino het snow (anery)

75% of half will be 3 out of 8 will be het anery 66% het albino



0.1 Albino Het Snow BCI x 1.0 Anery Het Snow BCI

lets break this one down too

anery x het anery which would result in half anery and half hat anery

albino x het albino would result in half albinos and half hets

now put those two together

1 out of 4 will be snow
1 out of 4 will be anery het snow
1 out of 4 will be albino het snow
1 out of 4 will be dh snow

I hope that this will be correct and simple enough for you to understand.